0.308 g magnesiumsulphate, that contains crystal water, isdissolved in water, så the total volume is 125.0 mL. To completelyprecipitate the suflation as barium sulfate in 25.0 mL of thissolution, 5.0 mL of 0.050 M barium hydroxide is required.
Calculate how many moles of crystal water are in 1 mole ofmagnesium sulfate.
I am lost in this one, hope for some help :)
