1.
Mg(s) + 2 HCl(aq) ---> MgCl2(aq) + H2(g)
No of mol of Mg = 0.45/24 = 0.01875 mol
No of mol of HCl = 5/1000*1 = 0.005 mol
limiting reactant is HCl
No of mol of H2 produced = 0.005/2 = 0.0025
mol
Volume of H2 = nRT/P
    =
0.0025*0.0821*298/((762-23.35)/760)
  = 0.063 L
   = 63 ml
2.
2 CO2(g) + H2O(â„“) ----> C2H2(g) + (5/2)
O2(g)Â Â DHrxn = 1299.5 kj
2* ( C(s) + O2(g) ---> CO2(g)
)Â Â Â Â Â Â Â Â Â Â Â Â Â Â
DHrxn = -393.5*2
     H2(g) + (1/2) O2(g)
--->
H2O(â„“)Â Â Â Â Â Â Â Â Â Â
DHrxn = -285.8
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  2C(s) + H2(g) ---> C2H2(g) Â
DHrxn = 1299.5+2*-393.5+(-285.8) = 226.7 kj
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