5C2O42- + 2MnO4- + 16H+
---------> 2Mn+2 +10Co2 + 8H2O
no of moles of Na2C2O4 = W/G.M.Wt
                                        Â
= 0.268/134 = 0.02moles
5 moles of Na2C2O4Â Â = 2 moles of KMnO4
0.02 moles of Na2C2O4 = 2*0.02/5Â Â = 0.008 moles of
KMnO4
molarity of KMnO4Â Â = no of moles /volume in L
0.05Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
= 0.008/volume in L
volume in
LÂ Â Â Â Â Â Â Â Â Â Â Â
= 0.008/0.05 = 0.16 L = 160ml
2. %
C2O42-Â Â Â Â Â Â Â Â Â
= 78*100/134Â Â = 58.2%
%
C2O42-Â Â Â Â Â Â Â Â Â Â
= 2*78*100/575.4Â Â = 27.11%
 Â
