1. Olive oil has a saponification value of 190 mg KOH per gram.This means that it takes 190 mg of potassium hydroxide to reactcompletely with 1 g of olive oil.
(a) What is the mole ratio for the reaction of a triglyceridewith KOH?
(b) Divide 0.190 g of KOH by its molar mass to calculate thenumber of moles of KOH that will react with 1 g of olive oil.
(c) Use the answers to (a) and (b) to determine the number ofmoles corresponding to 1 g of olive oil. Divide 1 g by this numberof moles to calculate the average molar mass (g/mole) of oliveoil.
