1. One out of four Americans over age 55 has eaten pizza for
breakfast. P(Eaten Pizza)...
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1. One out of four Americans over age 55 has eaten pizza forbreakfast. P(Eaten Pizza) = 0.25. If a sample of 10 Americans overthe age of 55 is selected at random, find the probability that atmost 3 have eaten pizza for breakfast. Use the binomialformula.
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One out of four Americans over age 55 have eaten pizza forbreakfast ie PEaten Pizza025p Therefore
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