As it is parallel reactions A -> B and A
->Â Â C
The rate of the reaction = - -rA->B + ( -rA->C) = -kB [2M]
- kC [2M]
                                              Â
  -r      = 0.6 [2]
mole/L.sec
                                                           Â
= 1.2 mole/L.sec
                                                 Â
-1/rA = 0.833 mole/L.sec
We know the formula for total required volume = Q x CA0 / -rA =
4 L/ 60 sec x 2 M / 0.833 mole/L.sec  = 0.16 L
