1) What is the pH at the equivalence point in the titration of a 21.9 mL...

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1) What is the pH at the equivalence point in the titration of a21.9 mL sample of a 0.456 Maqueous hypochlorous acid solution with a0.494 M aqueous potassiumhydroxide solution?
pH =
2) When a 29.8 mL sample of a0.430 M aqueous hydrocyanic acidsolution is titrated with a 0.373 M aqueouspotassium hydroxide solution, what is the pH after51.5 mL of potassium hydroxidehave been added?
pH =

Answer & Explanation Solved by verified expert

3.5 Ratings (312 Votes)

millimoles of HClO = 21.9 x 0.456 = 9.9864

At equivalence point :

mmoles of acid = mmoles of KOH

9.9864 = 0.494 x V

V = 20.22 mL

here salt only remains.

salt concentration = 9.986 / (21.9 + 20.22) = 0.237 M

pH = 7 + 1/2 (pKa + log C)

Â Â Â Â = 7 + 1/2 (7.46 + log 0.237)

pH = 10.42

mmoles of HCN = 29.8 x 0.430 = 12.814

mmoles of KOH = 51.5 x 0.373 = 19.2095

HCNÂ Â +Â Â Â KOHÂ Â Â Â -------->Â Â KCNÂ Â Â + H2O

12.8Â Â Â Â Â Â Â Â Â 19.2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â 0

0Â Â Â Â Â Â Â Â Â Â Â Â Â Â 6.40Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 12.8

here strong base reamins.

[OH-] = 6.40 / 29.8 + 51.5 = 0.0787 M

pOH = 1.10

pH = 12.90

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1) What is the pH at the equivalence point in the titration of a 21.9 mL...

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Chemistry

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