The number of mols of NH4Cl = (10.5 mL)(0.100 M) =
1.05 mmol
The number of mols of NaOH = (2.00 mL)(0.100 M) = 0.2 mmol
Here, the resultant reaction -
         Â
NH4+ (aq) + OH- (aq)
<--------> NH3 (aq) + H2O (l)
        1.05 mmol
  0.2
mmol                Â
0
         Â
-0.2 mmol    -0.2
mmol           Â
+0.2 mmol
         0.85
mmol    Â
0Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.2 mmol
So the resulting solution will be buffer. So option e)
correct.
