Given
              Â
Volume (V) = 12 liter
            Â
Pressure(P) = 285 Torr = 0.00132 atm
              Â
Temperature = -110Ëšc = 163 K
        So, According
to the equation PV = nrt
               0.00132
×12 = n × 0.082 × 163
              Â
n = 0.01584 / 13.366
                  Â
= 0.0011 mole
For SO2 1 mole = 64 gm
         Â
0.0011 mole = 0.0011× 64
        Â
                       =
0.0704 gm
So, 0.0704 gm of SO2 is taken.
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