1.810 g chlorine in methanol is added to 2.200 g of zinc metal. After the reaction...

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1.810 g chlorine in methanol is added to 2.200 g of zinc metal.After the reaction is complete, the remaining unreacted zinc wasweighed as 0.5260 g. Using the masses of the reacted zinc andchlorine, calculate the empirical formula of zinc chloride.

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3.8 Ratings (751 Votes)

Mass of Zn reacted = 2.200 - 0.5260 = 1.674 g. Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â

elementÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â massÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â molesÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â simplest ratio

ZnÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1.674Â Â Â Â Â Â Â Â Â Â Â Â 1.674/65 = 0.0258Â Â Â Â 0.0258/0.0258 = 1

ClÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 1.810Â Â Â Â Â Â Â Â 1.810 / 35.5 = 0.0510Â Â Â Â 0.0510 / 0.0258 = 2 (approx.)

Therefore, emperical formula of zinc chloride = ZnCl2

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1.810 g chlorine in methanol is added to 2.200 g of zinc metal. After the reaction...

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Question

Chemistry

1.810 g chlorine in methanol is added to 2.200 g of zinc metal.After the reaction is complete, the remaining unreacted zinc wasweighed as 0.5260 g. Using the masses of the reacted zinc andchlorine, calculate the empirical formula of zinc chloride.

Answer & Explanation Solved by verified expert

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