1A. normality of KOH = w/mwt*1000/V
                   Â
= (0.251/56.1)*(1000/100)
                    Â
= 0.45 N
     pH = 14-
(-log(OH-))
        = 14-
(-log0.45)
        =
13.65
1B. as H2SO4 is strong acid , it can donates proton
easily , so that equilibrium shifts leftside
2. Na3PO4 - Is a salt of weakacid,strongbase . so that
it is basic in nature.
2B. the pH of HA- depends upon ka2 only
  so that,
  pH = 1/2(pka2-logC)
  pka2 = -logka2 = -log(6.1*10^-5) = 4.215
     = 1/2(4.215 -
log0.1)
     pH = 2.6075