For the precipitation reaction,
(a) moles of C2O4^2- in solution before precipitation = 0.4324
g/128.097 g/mol = 0.0034 mol
(b) concentration of [Ca2+] If all has precipitated =
0.0034/0.175 = 0.019 M
ICE chart
                  Â
CaC2O4 <==> Ca2+ + C2O4^2-
IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0.019Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
-Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
-
CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
-x                 Â
+x           Â
+x
EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
(0.019 - x)Â Â Â Â Â Â Â Â Â
x               Â
x
Ksp = [Ca2+][C2O4^2-]
[Ca2+] = sq.rt.(1.3 x 10^-8) = 1.14 x 10^-4 M
(c) dissolved Ca2+ = 1.14 x 10^-4 x 0.175 x 40.08 = 0.0008 g
(d) mass of Ca in precipitate = 0.019 x 0.175 x 40.08 - 0.0008 =
0.0125 g
(e) Percentage of original calcium lost to the filtrate = 0.0008
x 100/0.133 = 0.60%