1)Write the complete equation (balanced with states) for thereaction between potassium chloride and lead (II) nitrate?
2) Which precipitate forms in the above mentioned reaction?
3) You mix 16.00 mL of 0.778 M lead (II) nitrate with 18.00 mLof 0.813 M potassium chloride, and collect and dry the precipitate.Calculate the following:
a) Moles of lead (II) nitrate used:
b)Moles of potassium chloride used:
c) Moles of precipitate expected from lead (II) nitrate:
d) Moles of precipitate expected from potassium chloride:
e) Compare parts c and d to indicate the limiting reactant.
f) What mass of precipitate do you expect to obtain from thisreaction?
g) If the actual yield of the precipitate you recover is 0.916g,what is the percent yield of the precipitate?
show work please
