a)
diseased people = (9+16)/2006 = 1.25%
b)
percent of the exposed persons have disease = 9/(9+992)*100=
0.90%
c)
odds of disease among the exposed = 9/992 = 0.00907
d) odds of disease among the unexposed=16/989= 0.0162
e) odds ratio = (9/992)/(16/989) = 0.5608
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         This means
that the odds of developing the disease for those exposed to the
risk factor is 0.56  times the odds  of
developing the condition for those that were not exposed to the
risk factor       Â
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