ball A mass = 0.26 kg
ball B mass = 0.07 kg
i) during collision momentum is conserved
momentum before collision  = momentum after
collision
lets take the velocity of ball B after collision be v
0.26(3.2) + 0.07(0) = 0.26(2.3) + 0.07(v)
0.07(v) = 0.26( 3.2-2.3)
v = 3.343 m/sec
ii) maximum height reached by the ball B after collision is =
v*v/2*g
                                                                                           Â
= 0.57 mts
b) mass of vehicle = 1800 kg
speed of vehicle is = 15.4 m/sec
frictional force is balanced by centripetal force
frictional force       Â
  =   m*v*v/r
12400Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
= 1800* 15.4*15.4Â Â /r
r        Â
=Â Â 1800*15.4*15.4/12400
radius (r)  = 34.43 mts   Â
