3 20 3 18 10 Step 6 Sixth allocate in 3 4 cell X34 min 5 5 5 4 18 5 5 3 The initialz basic feasible solution is given by X11 5 X12 10 X22 5 X23 15 X24 5 X34 5 1 2 3 4 5 10 1 5 2 3 b 1 2 3 1 6 8 9 4 6 10 12 14 16 18 Minimum transportation cost 5 10 10 0 5 7 15 9 5 20 5 18 Rs 410 Exercise 1 Using North West Corner rule find out the initial basic feasible solution to the following TP 2 Least Cost Method 5 0 0 2 3 4 a 4 1 5 14 15 2 7 16 3 6 2 5 10 15 4 35 20 7 9 20 5 20 11 5 The procedure is as follows Step 1 Determine the smallest cost in the cost matrix of the transportation table Let it be Cij Allocate x min a b in the i j cell Step 2 If x j a cross off ith row of the transportation table and decrease b by aj If xij b cross off jth column of the transportation table and decrease a by bj If Xij a bj cross off either the first row or the first column but not both Step 4 Reneat stens 1 and 2 for the resulting table Reduce transportation table
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