39 What is the theoretical yield (in g of precipitate) when 15.8 mL of a 0.572 M...

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39
What is the theoretical yield (in g of precipitate) when 15.8 mLof a 0.572 M solution of iron(III) chloride is combined with 16.8mL of a 0.687 M solution of lead(II) nitrate?

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Given the volume of IronIII chloride FeCl3 158 mL 158mLx1L 1000 mL 00158 L Concentration of FeCl3 0572 M Hence moles of FeCl3 MxV 0572M x 00158L 000904 mol Given the volume of leadII nitrate PbNO32 168 mL See Answer

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39 What is the theoretical yield (in g of precipitate) when 15.8 mL of a 0.572 M...

70.2K

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Chemistry

39
What is the theoretical yield (in g of precipitate) when 15.8 mLof a 0.572 M solution of iron(III) chloride is combined with 16.8mL of a 0.687 M solution of lead(II) nitrate?

Answer & Explanation Solved by verified expert

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39 What is the theoretical yield (in g of precipitate) when 15.8 mL of a 0.572 M...

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Chemistry

39What is the theoretical yield (in g of precipitate) when 15.8 mLof a 0.572 M solution of iron(III) chloride is combined with 16.8mL of a 0.687 M solution of lead(II) nitrate?

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39
What is the theoretical yield (in g of precipitate) when 15.8 mLof a 0.572 M solution of iron(III) chloride is combined with 16.8mL of a 0.687 M solution of lead(II) nitrate?