4.3120 g KNO3, 1.2345 g of CuCl2*2H2O, and 0.5678 g of
BaCl2*2H2O are used to prepare...
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4.3120 g KNO3, 1.2345 g of CuCl2*2H2O, and 0.5678 g ofBaCl2*2H2O are used to prepare K2CuBa(NO2)6. Calculate thetheoretical yield of K2CuBa(NO2)6 in grams.
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CuCl22H2O BaCl22H2O 6 KNO2 K2CuBa NO26 4 H2O 4 KCl Step 1 Calculate moles of CuCl22H2O 12345 g of CuCl22H2O given Molar mass ofCuCl22H2O 17048256 gmole Moles of CuCl22H2O 12345 g17048256 gmole 000724 moles Step 2 Calculate moles of KNO2
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