500.0 mL of 0.150 M NaOH is added to 605 mL of 0.200 M weak...
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500.0 mL of 0.150 M NaOH is added to 605 mL of 0.200 M weak acid(Ka = 5.15 × 10-5). What is the pH of the resulting buffer?
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Answer We are given weak acid HA 0200 M volume 605 mL Ka 515E5 NaOH 0150 M volume of NaOH 5000 mL Calculation of moles First we need to convert the given volume to L Volume of weak acid We know 1 mL
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