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7. The University Skydiving Club has asked you to plan a stunt for an air show....

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Physics

7. The University Skydiving Club has asked you to plan a stuntfor an air show. In this stunt, two skydivers will step out ofopposite sides of a stationary hotair balloon 1500 meters above theground. The second skydiver will leave the balloon 20 seconds afterthe first skydiver but you want them both to land on the ground atthe same time. The show is planned for a day with no wind so assumethat all motion isvertical. To get a rough idea of the situation,assume that a skydiver will fall with a constant acceleration of9.80 m/s2before the parachute opens. As soon as the parachute isopened, the skydiver falls with a constant velocity of 3.2 m/s. Ifthe first skydiver waits 3 seconds after stepping out of theballoon before opening her parachute, how long must the secondskydiver wait after leaving the balloon before opening hisparachute?

Answer & Explanation Solved by verified expert
4.0 Ratings (807 Votes)
Find an equation for the distance the first jumper falls You can calculate how far the first falls before pulling open her parachute using D05gt2 D 059832441 m Then you have a constant velocity function with a    See Answer
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