Null hypothesis: Ho:All lanes are equally preferred
Alternate hypothesis:Ha: some lanes are preferred over
others
|
degree of freedom =categories-1= |
3 |
|
| for 0.05
level and 3 df :crtiical value X2 = |
|
7.815 |
| Decision
rule: reject Ho if value of test statistic X2>7.815 |
|
applying chi square goodness of fit test: |
|
|
         Â
relative |
observed |
Expected |
|
Chi square |
|
category |
frequency(p) |
Oi |
Ei=total*p |
|
R2i=(Oi-Ei)2/Ei |
|
1 |
0.2500 |
294.0 |
250.00 |
|
7.7440 |
|
2 |
0.2500 |
276.0 |
250.00 |
|
2.7040 |
|
3 |
0.2500 |
238.0 |
250.00 |
|
0.5760 |
|
4 |
0.2500 |
192.0 |
250.00 |
|
13.4560 |
|
total |
1.000 |
1000 |
1000 |
|
24.4800 |
|
|
|
|
|
|
|
|
test statistic X2 = |
24.480 |
|
|
|
|
since test statistic falls in rejection region we reject null
hypothesis |
| we have
sufficient evidence to conclude that some lanes are preferred over
others |
|
