A:- a) The heat lost by the water is calculated as,
Equilibrium temperature of the mixture = 10.93oC.
Initially temperature of water = 20oC,
The heat lost by the water = 4.184 joules * 100 g * 20-10.93
                                    Â
= 4.184 joules * 100 g * 9.07oC
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= 3794.89 joules
b) The heat gained by the melted water of the ice cube =
4.184 joules * 10 g * 9.07oC
                                                                             Â
= 436.63 joules
c) The heat absorbed by the ice to achieve melting =
4.184 joules * 10 g * 9.07oC
                                                                        Â
= 436.63 joules
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