A:- From the ideal gas equation, PV = nRT we have to solve this
problem as,
=> Partial pressure of argon, Pargon = nRT / V
                                      Â
= ((1.45 g Ar) / (39.9480 g Ar/mol)) x (0.08206 L atm/K mol) x (25
+ 273.15)K / (1.00 L)
Partial pressure of argon, Pargon =0.888 atm
=> Partial pressure of ethane, Pethane =
Ptotal - Pargon
                                    Â
           Â
= (1.450 - 0.888)
                                          Â
Pethane = 0.562 atm
