A 1 100 L sample of HCl gas at 25C and 732 0 mm Hg was absorbedcomplet...

A 1.100 L sample of HCl gas at 25âˆ˜C and 732.0 mm Hg was absorbed completely...

3.8 Ratings (557 Votes)

The number of mols of HCl = n = PV / RT = (732/760) atm*1.100 L /(0.0821*298)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.0433 mol

Thus, concentration of the solution = 0.0433 mol / 0.265 L = 0.163 mol/L

pH = -log [H⁺] = -log (0.163) = 0.786

--------------------------------------------------------------------------------------------------------------------------------------------------

Depression in freezing point = K_f* m

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (1.86⁰C) (6.9 g / 106 g/mol) (1000 / 265)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.45⁰C

Hence - Freezing point of the substance = -0.45⁰C

------------------------------------------------------------------------------------------

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member