Masses m = 20 g
           M
= 30 g
Initial velocities u = 2 i
                     Â
U = 1x cos 30 ( -i) + 1 x sin 30 ( -j)
                         Â
= -0.866 i -0.5 j
Let the velocity of the resulting 50 g blob of clay be v
From law of conservation of momentum ,
mu+ MU = ( m+ M) v
40 i -25.98 i - 15 j = 50 v
14.01 i - 15 j = 50 v
v = 0.2803 i - 0.3 j
Speed of the resulting 50 g clay v = √[ 0.2803 2 +
(-0.3) 2 ]
                                                  Â
= 0.4105 m / s
