C3H5O(COOH)3 (aq) + 3 NaOH(aq)
--------------------> Na3C3H5O(COO)3(aq) + 3 H2O (l)
moles of NaOH = 20.3 x 0.113 / 1000 = 2.2939 x 10^-3
here
1 mol citric acid react -------------- 3 moles of NaOH
so moles of citric acid = moles of NaOH / 3
                                 Â
= 2.2939 x 10^-3 / 3
                                Â
= 7.65 x 10^-4
molar mass of citric acid = 192.12 g/mol
mass 0f citric acid = moles x molar mass
                            Â
= 7.65 x 10^-4 x 192.12
                            Â
= 0.147 g
% citric acid = (0.147 / 2.00 ) x 100
              Â
  = 7.34%
