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  3. a 27.5 l sample of oxygen gas is at 25°c and 1.

A 27.5 L sample of oxygen gas is at 25°C and 1.05 atm. If the gas...

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Chemistry

A 27.5 L sample of oxygen gas is at 25°C and 1.05 atm. If thegas is cooled to –

40.°C while the pressure is increased to 2.00 atm, calculate thenew volume of the

gas.

Can u please show with dymentional analysis?

Answer & Explanation Solved by verified expert
4.4 Ratings (763 Votes)

Initial conditions:

Pressure P1 = 1.05 atm

Volume V1 = 27.5 L

Temperature T1 = 25 oC = 25 + 273 K = 298 K

Final conditions:

Pressure P2 = 2 atm

Volume V2 = ? L

Temperature T2 = -40 oC = -40+ 273 K = 233 K

We knaow that P1V1/T1 = P2V2/T2

                       V2 = (P1V1/T1) (T2/P2)

                           = ( 1.05 atm x 27.5 L/ 298 K ) ( 233 K/ 2 atm)

                          = 11.28 L

                     V2 = 11.28 L

Therefore,

new volume of the gas = 11.28 L
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