Given mass of NaOH , m = 29.0 g
MOlar mass of NaOH is = At.mass of Na + At.mass of O + At.mass
of H
                                     Â
= 23 + 16 + 1
                                    Â
= 40 g/mol
So the number of moles of NaOH , n = mass/molarmass
                                                         Â
= 29.0 g / 40 (g/mol)
                                                         Â
= 0.725 mol
Volume of the solution , V = 1.60 L
Molarity of the solution , M = number of moles / volume in L
                                        Â
= 0.725 mol / 1.60 L
                                        Â
= 0.453 mol / L
                                       Â
= 0.453 M
So Molaity of the solution is 0.453 M
Therefore option (B) is correct.