The resistance of the wire is
            Â
R = ?L/(?r^2)
Here ? = 1.72 x 10-8 ?/m
        L =
(19)(?d)
             =
(19)(?(2.80x 10^-3 m))
           Â
= 0.167 m
        r = (2.80 x
10^-3 m)/2
          =
1.40Â Â x 10^-3 m
       R = ?L/(?r^2)
          Â
= ( 1.72 x 10-8 ?/m) (0.167 m)/(?(
1.40Â Â x 10^-3 m)^2)
          Â
= 4.66x 10^-4 ?
The formula for the induced emf is
        e =- NA
(?B/?t)
           =-
(19)(?(0.165m)^2)(0.0095 T/s)
          = -
0.0146 V
So the magnitude of the induced current is
           Â
I= e/R
             Â
=(0.0146 V)/( 4.66x 10^-4 ?)
               =
31.34 A
