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  3. a. a 75.0-mlml volume of 0.200 mm nh3nh3 (kb=1.8Ã

A. A 75.0-mLmL volume of 0.200 MM NH3NH3 (Kb=1.8×10−5Kb=1.8×10−5) is titrated with 0.500 MM HNO3HNO3. Calculate the...

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Chemistry

A. A 75.0-mLmL volume of 0.200 MM NH3NH3(Kb=1.8×10−5Kb=1.8×10−5) is titrated with 0.500 MM HNO3HNO3.Calculate the pHpH after the addition of 11.0 mLmL of HNO3HNO3.

B. A 50.0-mLmL volume of 0.15 MM HBrHBr is titrated with 0.25 MMKOHKOH. Calculate the pHpH after the addition of 15.0 mLmL ofKOHKOH.

C. A 52.0-mLmL volume of 0.35 MM CH3COOHCH3COOH(Ka=1.8×10−5Ka=1.8×10−5) is titrated with 0.40 MM NaOHNaOH.Calculate the pHpH after the addition of 17.0 mLmL of NaOHNaOH.

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3.9 Ratings (646 Votes)
A A 750mLmL volume of 0200 MM NH3NH3 Kb18105Kb18105 is titrated with 0500 MM HNO3HNO3 Calculate the pHpH after the addition of 110 mLmL of HNO3HNO3 pKb of NH3 log 18x105 475 NH3 HNO3 NH4NO3 75x02 15 11x05 55 0 initial mmoles    See Answer
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