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A baseball player's batting average is 0.337, which can be interpreted as the probability that he got a hit each time at bat. Thus, the probability that he did not get a hit is 1-0.337=0.663. Assume that the occurrence of a hit in any given at-bat has no effect on the probability of a hit in other at-bats. In one game, the player had 4 at-bats. What is the probability that he had 3 hits?What expression can be used to calculate the probability?A. [7 4] (0.337)? (0.663)?B. [4 3] (0.337)? (0.663)C. [4 3] (0.337+0.663)D. [4 3] (0.337) (0.663)The probability that the player had 3 hits in 4 at-bats is(Round to three decimal places as needed.)
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