A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s....

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A car accelerates uniformly from rest and reaches a speed of22.0 m/s in 9.00 s. If the diameter of the tire is 58.0 cm, find(a) the number of revolutions the tire makes during the motion,assuming that no slipping occurs. (b) What is the final angularspeed of a tire in revolutions persecond?Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
Answer:Â Â (54.3 rev, 12.1 rev/s) --> please show mehow to get this answer!

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4.4 Ratings (766 Votes)

22ms from rest with constant acceleration means that the average speed was 11ms Therefore you can get the distance travelled by distance time average speed distance 9s 11ms 99m See Answer

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A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s....

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Physics

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