A clean surface of a metal in a vacuum tube is irradiated with a monochromatic...
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A clean surface of a metal in a vacuum tube is irradiated with a monochromatic light of wavelength 500nm and the resulting photoelectric current is measured by the ammeter A as shown in the circuit It is found that it the voltmeter V reading is greater than 0 8V the ammeter shows zero reading Now with a second source of light the ammeter reading vanishes when the voltmeter regarding is changed to 1 2 V Then Battery B with rheostat R makes a potential divider circuit wwwwwwwwww 500m Given h 6 6x10 Jsc 3x10 ms e 1 6x10 C A The frequency of second source is 6 97x10 Hz B The kinetic energy of photoelectrons due to first source is less than or equal to 08 eV C The work function of emitting surface is 1 68eV D The kinetic energy of photoelectrons due to second source is 1 2 eV
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