Diameter (d) of the Ferris wheel = 35.0 m
Radius (r) of the Ferris wheel = (35.0m)/2
                                              Â
= 17.5 m
Initial velocity (u) of the wheel = 0
Final velocity (v) of the wheel = 2.20 m/s
Time (t) taken to reach its maximum speed = 15.0 s
b)
Then linear acceleration (a) of the wheel is
                    Â
a = (v - u)/t
                       Â
= (2.20m/s - 0)/(15.0s)
                       Â
= 0.147 m/s^2
a)
Then angular acceleration (a) of the wheel is
                   Â
a = a / r
                      Â
= (0.147 m/s^2) / (17.5m)
                      Â
= 0.0084 rad/s^2
