A flask contains 30.5 g of oxygen gas, 45.7 g of sulfur dioxide gas and 23.9...

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A flask contains 30.5 g of oxygen gas, 45.7 g ofsulfur dioxide gas and 23.9 g of fluorine gas. If the totalpressure of the flask is 1.45 atm, what is the partial pressure ofsulfur dioxide gas in the flask?

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3.7 Ratings (271 Votes)

moles of O2 = mass / molar mass

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 30.5 / 32

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.953

moles of SO2 = 45.7 / 64

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.714

moles of F2 = 23.9 / 38

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.629

mole fraction of SO2 = moles of SO2 / total moles

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.714 / (0.953 + 0.714 + 0.629)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.311

partial pressure of = mole fraction x total pressure

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.311 x 1.45

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.451 atm

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A flask contains 30.5 g of oxygen gas, 45.7 g of sulfur dioxide gas and 23.9...

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80.2K

Verified Solution

Question

Chemistry

A flask contains 30.5 g of oxygen gas, 45.7 g ofsulfur dioxide gas and 23.9 g of fluorine gas. If the totalpressure of the flask is 1.45 atm, what is the partial pressure ofsulfur dioxide gas in the flask?

Answer & Explanation Solved by verified expert

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