The solubilities of N2 = 0.0175 g/L
molarity of N2 = 0.0175 / 28 = 0.000625
moles = molarity x volume
volume = 1 L
so moles = molarity
moles of N2 = 0.000625
The solubilities of O2 = 0.0393 g/L
molarity of O2 = 0.0393 / 32 = 0.00123
moles of O2 = 0.00123
total moles = moles of N2 + moles of O2 = 0.000625 + 0.00123
                Â
= 0.001855
mole fraction of N2 = moles of N2 / total moles
                             Â
= 0.000625 / 0.001855
                             Â
= 0.3369
compostion of N2 = 33.69%
mole fraction of O2 = 0.6631
composition of O2 = 66.31%
