A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr of N2(g), and 65.7 Torr of...

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A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr ofN2(g), and 65.7 Torr of Ar(g). Calculate the mole fraction, X, ofeach of these gases.

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P_H2Â Â Â =413 Torr

P_N2Â Â Â = 391.5 Torr

P_ArÂ Â Â Â = 65.7 Torr

Total pressure = P_H2 + P_N2 + P_Ar

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 413+391.5 +65.7 =870.2 Torr

partial pressureÂ Â = mole fraction of gas* total pressure

P_H2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = X_H2 * P_T

413Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = X_H2 *870.2

X_H2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 413/870.2Â Â Â = 0.475

P_N2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = X_N2 * P_T

391.5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = X_N2 *870.2

X_N2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 391.5/870.2Â Â = 0.45

P_Ar Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = X_Ar * P_T

65.7Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = X_Ar *870.2

X_ArÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 65.7/870.2Â Â = 0.0755

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A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr of N2(g), and 65.7 Torr of...

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60.1K

Verified Solution

Question

Chemistry

A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr ofN2(g), and 65.7 Torr of Ar(g). Calculate the mole fraction, X, ofeach of these gases.

Answer & Explanation Solved by verified expert

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