5.0% by mass of glucose solution is 5.0 g of Glucose present in
100 g of solution
Given density of solution , d= 1.02 g/mL
So Volume of solution , V = mass / density
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= 100 g / 1.02 (g/mL)
                                 Â
= 98.0 mL
From the data 100g = 98.0 mL of the solution contains 5.0 g of
glucose
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100.0 mL of the solution contains M g of glucose
                                  Â
M = ( 100.0x5.0) / 98.0
                                     Â
= 5.1 g
Therefore the mass of glucose should present is 5.1 g
