(1)flow rate of CH4 =0.9 x 400Kg/s
                        Â
=360Kg/s
mols of air in a second=
400x1000g/29gmol-1(considering oxygen and nitrigen
present in air)
                                             Â
=13793.1034mol
mols of CH4 in a second=
360x1000g/16gmol-1
                                             Â
=22500.0000mol
mol ratio= 13793.1034mol:22500.0000mol
number of nitrogen moles=79% x13793.1034mol=10853.89mol
number of oxygen moles=21% x22500.0000mol=4725mol
CH4+2O2----------> CO2 + 2H2O accordingly 11250 mols of
methane reacts in a second
OUT PUT STEAM
number of water mols =4725 mol
number of carbondioxide mols=2362.5 mol
number of nitrogen molesl=10853.89mol
remaining methane mols=22500- 2362.5 mol=20137.5mol
toal number of mols in output=38078.89mol
MOL FRACTIONS
WATER=11250/38078.89=0.29
carbondioxide=2362.5/38078.89=0.06
nitrogen=10853.89/38078.89=0.28
methane=20137.5/38078.89=0.52
BY MULTIPLYING EACH MOLS BY MOLECULAR WEIGHT OU CAN CALCULATE
THE MASS FRACTIONS
