number of moles of KSCN = ((8.5 * 10^-3) * 11.5) / 1000 = 9.775
* 10^-5
number of moles of Fe(NO3)3 = ((3.7*10^-2)*10.4) / 1000 = 3.848
* 10^-4
3 KSCN (aq) + Fe(NO3)3 (aq) ---------> Fe(SCN)3 (s) + 3 KNO3
(aq)
3 mole of KSCN requires 1 mole of Fe(NO3)3
9.775 * 10^-5 moles of KSCN requires (1/3) * 9.775 * 10^-5
                                                                   Â
= 3.2583 * 10^-5 moles
remaining moles of Fe(NO3)3 = (3.848 * 10^-4) - (3.2583 * 10^-5)
= 3.5222 * 10^-4
concentration of Fe+3 = (3.5222 * 10^-4) * (1000 / (11.5 + 6.3 +
10.4))
                                     Â
= 0.01249 M
