Â
2 Cl2(g) + 2 H2O(g) ----> 4 HCl(g) + 1 O2(g)
initial       0.2063
mol  0.2093 mol   0.1887 mol 0.09871
mol
change      Â
2*0.0405 mol 2*0.0405 mol 4*0.0405 mol 0.0405 mol
    Â
equilibrium   0.2873 mol   0.2873
mol  0.0267 mol 0.05821 mol
at equilibrium
ntotal = 0.2873 +0.2873 +0.0267 +0.05821 = 0.66
mol
Ptotal = ntotal*RT/V
      =
0.66*0.0821*575/1
      = 31.16
atm
partial pressure of Cl2(pCl2) =
(ncl2/ntotal)*ptotal
                             Â
= 0.2873/0.66*31.16
       Â
       Â
   = 13.56 atm
   pH2O = 13.56 atm
  pHCl = (0.0267/0.66)*31.16 = 1.26
atm
  pO2 = (0.05821/0.66)*31.16 = 2.75
atm
  Kp = pHCl^4*pO2 / pCl2^2*pH2O^2
      =
(1.26^4*2.75/(13.56^2*13.56^2))
Kp = 2.05*10^-4
