Speed of the paper (in ground frame) = Speed with which he can
throw + speed of the cycle
                                                      Â
=5.1 m/s +8.3 m/s
                                                      Â
=13.4
m/s (Ans.)
CONCEPT:
The concept is not much difficult but requires a general
understanding of what is actually going on. I hope you understood
that the paper's velocity will be added up with the velocity that
he is already having (cycle's velocity) to get the net paper
velocity in ground frame.
Still comment in case of any doubt.
