A particle moves in the xy plane with constant acceleration. Att = 0 the particle is at vector r1 = (3.6 m)i + (2.8 m)j, withvelocity vector v1. At t = 3 s, the particle has moved to vector r2= (11 m)i − (1.8 m)j and its velocity has changed to vector v2 =(4.6 m/s)i − (6.7 m/s)j. (a) Find vector v1. vector v1 = m/s
(b) What is the acceleration of the particle? vector a =m/s2
(c) What is the velocity of the particle as a function of time?vector v(t) = m/s
(d) What is the position vector of the particle as a function oftime? vector r(t) = m
