solution)
1% Na2H
PO4 means 1 gram of
Na2H PO4 in 100 ml
of the solution .
So amount of Na2H
PO4 in 47 ml = 1 * 47 /100= 0.47 gram = 470
mg
So number of moles of Na2H
PO4 = 470/141.96 = 3.31 millimoles
So number of equivalents of po4- = 3.31 new
So 3.31 m Eq of po4- present in 500 ml of solution.
So 0.5 mEq present in 500/3.31 * 0.5 = 302 ml
Infusion rate per minute = 302/60 = 5.03 ml/minute.
So the infusion rate should be 5.03 ml/minute.
hence solved
