The ascending velocity (or) initial velocity of camera, u = 15
m/s
   The height at which it will drop, h = 54 m
A)
We have, h = (1/2)gt^2 - ut
                  (1/2)gt^2
- ut - h = 0
                  (1/2)(9.8)t^2
- 15t - 54 = 0
The time taken by camera to reach the ground, t = 5.19 sec
B)
    The velocity at which it hits the ground
is given by
                        v
= u + at
                           =
15 - 9.8 x 5.19
                           =
-35.86 m/s
