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A photographer in a helicopter ascending vertically at a constant rate of 15.0m/s accidentally drops a...

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Physics

A photographer in a helicopter ascending vertically at aconstant rate of 15.0m/s accidentally drops a camera out the windowwhen the helicopter is 54.0m above the ground.

a)How long will the camera take to reach the ground?

b)What will its speed be when it hits?

Answer & Explanation Solved by verified expert
4.0 Ratings (505 Votes)

The ascending velocity (or) initial velocity of camera, u = 15 m/s

   The height at which it will drop, h = 54 m

A)

We have, h = (1/2)gt^2 - ut

                  (1/2)gt^2 - ut - h = 0

                  (1/2)(9.8)t^2 - 15t - 54 = 0

The time taken by camera to reach the ground, t = 5.19 sec

B)

    The velocity at which it hits the ground is given by

                        v = u + at

                           = 15 - 9.8 x 5.19

                           = -35.86 m/s
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