By conservation of angular momentum:
  I ?initial = I?final
The moment of inertia for wheel is,
    Iwheel  = (1/2) M
R2
       Â
       = (1/2) *6.00 *
0.252
      Â
        =  0.1875
The moment of inertia for clay is,
Iclay = (1/2) M R2
      = (1/2) * 2.2*
0.0712
     =  0.00554
Therefore,
       Â
Iwheel * ?initial  = Â
(Iwheel + Iclay) * ?final
         Â
     (0.1875) * (1.6
rev/s)Â Â Â = (0.1875+ 0.00554) * ?final
          Â
                ?final=
1.55 rev /sec
