here conservation of angular momentum
that is
Li = Lf
     initial angular momentum = final
angular momentum
we know that angular momentum L = Iw   I is
sum of moment of inertia of two weights of mass 1 kr
each
Li = (mr1^2 +mr1^2)wi=
2mr1^2*wi
Lf = (mr2^2 +mr2^2)wf=
2mr2^2*wf
Li = Lf === > 2mr1^2*wi =
2mr2^2*wf
               Â
r2= r1(sqrt (wi / wf))
                    Â
= 0.75 sqrt(10*2*pi / 20*2*pi)
                    Â
= 0.75 sqrt(1/2)
                 Â
r2 = 0.53033 m
the new position of the weights from the rotational axis
is 0.53033 m
