A projectile is launched from ground level at angle θand speed v_0 into a headwind that causes a constanthorizontal acceleration of magnitude a opposite thedirection of motion.
Find an expression in terms of a and g for thelaunch angle that gives maximum range.
The answer is θ = 45 - (1/2)tan^-1(a/g)
The problem that I'm having is I have no idea how to get to thatanswer. Please do the problem and tell me where you got eachequation and what you are doing on each step. I'm beyond confusedas to how to get to that answer.
Thanks
