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A random rearrangement doe not separate out between repeated letters. Consider word CHRISTMASTIME. a) What's the expected...

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Basic Math

A random rearrangement doe not separate out between repeatedletters. Consider word CHRISTMASTIME.

a) What's the expected # vowels in first three letters of randomrearrangement of CHRISTMASTIME?

b) What's probability that all the S's happen before all the I'sin random rearrangement of CHRISTMASTIME?

c) What's probability that word CHRIST happens in consecutiveletters of uniform rearrangement of CHRISTMASTIME?

Answer & Explanation Solved by verified expert
4.0 Ratings (802 Votes)
a Total number of letters 13 Total number of vowels 4 Therefore the expected number of vowels in the first 3 letters of a random rearrangement here is computed as 4133 09231 Therefore 09231 is the expected number of    See Answer
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