1)
let r= k*[A]^x [B]^y
put the values from both experiments to get 2 equations
0.0841 = k* (0.00022)^x *
(0.00046)^y         Â
.....eqn 1
0.3035 = k* (0.00022)^x *
(0.00166)^y         Â
.....eqn 2
divide eqn 2 by 1
0.3035/0.0841 = (0.00166/0.00046)^y
3.61 = (3.61)^y
so,y=1
the order of the reaction with respect to B =1
2)
let r= k*[A]^x [B]^y
put the values from both experiments to get 2 equations
0.0000825 = k* (0.00057)^x *
(0.00067)^y         Â
.....eqn 1
0.0657= k* (0.00057)^x *
(0.00621)^y         Â
.....eqn 2
divide eqn 2 by 1
0.0657/0.0000825 = (0.00621/0.00067)^y
796.34 = (9.27)^y
take log on both sides
log (796.34) = y * log (9.27)
y= log (796.34) / log(9.27)
=3
so,y=3
the order of the reaction with respect to B =3
